Question

Solve the following quadratic equation for all values of x in simplest form.

Answer 1

`x=√(7),\:x=-√(7)`

Explanation:

Start by rewriting the equation to standard form
`ax^2+bx+c=0`.

`5(x^2-10)+5=-10,\\5x^2-50+5=-10,\\5x^2-35=0`.

Factor out the 5, then isolate
`x^2`:

`5x^2-35=0,\\5(x^2-7)=0,\\x^2-7=0,\\x^2=7,\\x=\pm √(7).`.

Therefore, the solutions to this quadratic are:

`x=√(7),\:x=-√(7)`