1 Answer

Jesse Buchanan · Answer 1 · 2022-05-12T13:10:35+0000

Answer:

$x=√(7),\:x=-√(7)$

Explanation:

Start by rewriting the equation to standard form
ax^2+bx+c=0 .

$5(x^2-10)+5=-10,\\5x^2-50+5=-10,\\5x^2-35=0$ .

Factor out the 5, then isolate
x^2 :

$5x^2-35=0,\\5(x^2-7)=0,\\x^2-7=0,\\x^2=7,\\x=\pm √(7).$ .

Therefore, the solutions to this quadratic are:

$x=√(7),\:x=-√(7)$

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