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PLEASEEEE HELPP

If 359 mL of a gas were contracted to only 269 mL, what would be the initial temperature of it if it measured 422 K after the change?

I NEED IT FAST!!

User Peleke
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1 Answer

5 votes

Answer:

T₁ = 563.19 K

Step-by-step explanation:

Given data:

Initial volume = 359 mL

Final volume = 269 mL

Final temperature = 422 K

Initial temperature = ?

Solution:

The given problem will be solve through the Charles Law.

Charles Law:

According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.

Mathematical expression:

V₁/T₁ = V₂/T₂

V₁ = Initial volume

T₁ = Initial temperature

V₂ = Final volume

T₂ = Final temperature

Now we will put the values in formula.

V₁/T₁ = V₂/T₂

T₁ = V₁T₂ / V₂

T₁ = 359 mL × 422 K / 269 mL

T₁ = 151498 mL.K / 269 mL

T₁ = 563.19 K

User Hibbem
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