Given vertices of triangle ABC are A(−1, 4) , B(3, 1) , and C(0,−3).
Slope of AB is :

Slope of BC is :
![m=(-3-1)/(0-3)=(4)/(3)[/tex.</p><p>Slope of AC is: </p><p>[tex]m=(-3-4)/(0-\left(-1\right))=-7.](https://img.qammunity.org/2019/formulas/mathematics/middle-school/392rlt7iixs9o3966s8vmct4dro0feoz02.png)
Slope of AB is negative reciprocal of slope of BC.
Therefore, AB and BC are perpendicular lines and triangle ABC is a right triangle.
The slope of AB is -3/4, the slope of BC is 4/3, and the slope of AC is -7. Triangle ABC is a right triangle because two of these slopes have a product of -1.