Question

What is the end behavior of the graph of the exponential function f(x)=b^x when 0

Answer 1

b)f(x) -->0, when x --->∞ and f(x)--->∞, when x--->-∞

Explanation:

First let's draw the graph.

Here f(x) = b^x, when 0 < b < 1

Here b greater than zero and less than 1.

Therefore, b must be number which is less 1 and greater 0.

Let's take b = 1/2 and the function becomes f(x) = (1/2)^x

Now let's draw the graph to find the answer.

In the graph,

f(x) -->0, when x --->∞ and f(x)--->∞, when x--->-∞

Therefore, answer is b)f(x) -->0, when x --->∞ and f(x)--->∞, when x--->-∞

Answer 2

The diagram shows the graph of the function
`f(x)=b^x.`

This graph is increasing, when b>1 and decreasing, when 0<b<1.

From this graph (in case 0<b<1) you can see that

• 
  `f(x)\to \infty,` when
  `x\to -\infty;`
• 
  `f(x)\to 0,` when
  `x\to \infty.`

Answer: correct option B.