Question

If we react 5.4g of sodium chloride with an unknown amount of fluorine gas, we produce 4.9g of sodium fluoride and 3.7g chlorine gas. How much fluorine was consumed in the reaction?

Answer 1

1.9g of F₂ were consumed in the reaction

Step-by-step explanation:

Based on the chemical reaction:

2NaCl + F₂ → 2 NaF + Cl₂

Where 2 moles of NaCl react per mole of F₂ to produce 2 moles of NaF and 1 mole of Cl₂

To understand in a better way how the reaction occurs we need to convert each mass of compound to moles:

Moles of NaCl -Molar mass: 58.44g/mol-:

5.4g * (1mol / 58.44g) = 0.092 moles NaCl

Moles of NaF -Molar mass: 41.988g/mol-:

4.9g * (1mol / 41.998g) = 0.12 moles NaF

Moles of Cl₂ -Molar mass: 70.90g/mol-:

3.7g * (1mol / 70.90g) = 0.052 moles Cl₂

That means approximately 0.1 moles of NaCl react with 0.05 moles of F₂ to produce 0.1moles of NaF and 0.05 moles of Cl₂.

0.05 moles of F₂ are:

0.05 moles * (38g/mol) =

1.9g of F₂ were consumed in the reaction