Question

Sam spun a spinner that is evenly spaced and numbered from 1 to 10. When it stopped, Sam spun it again. What is the probability that the spinner stopped on a number less than 4 on the first spin and on an odd number on the second spin?

a 1/5
b 1/10
c 3/20
d 2/25

Answer 1

2/10=1/5

your answer is A

Answer 2

C. 3/20

Explanation:

First, we need to find the probability of a number less than 4. Notice that there are only three possible events, number 1, number 2 and number 3.

So, the probability of a number less than 4 is

`P_(<4)=(3)/(10)=0.30 (or \ 30\%)`

On the other hand, there are 5 odd number, which are 1, 3, 5, 7 and 9. So, the probability of getting an odd number is

`P_(odd)=(5)/(10)=(1)/(2) =0.50 (or \ 50\%)`

Therefore, the probaility of getting these outcomes in two spins is

`P=(3)/(10) * (1)/(2)=(3)/(20)`

So, the right answer is C.