Answer:
Explanation:
We know that exponential formula of depreciation

where
P is the initial amount
x is the interest rate
A is the amount after t years
we are given
The annual rate of depreciation, x, on a car that was purchased for $9,000
so, P=9000
we can plug value it

we are given
when x=5 , A=4500
so, we can plug it and solve for x





so, interest rate is 13%
now, we can plug x
and we get


Graph: