Question

[2+(6times8)]-1 plz help

Answer 1

`Solution, \left[2+\left(6\cdot \:8\right)\right]-1=49`

`Steps:`

`\left[2+\left(6\cdot \:8\right)\right]-1`

`Follow\:the\:PEMDAS\:order\:of\:operations,\\\mathrm{Calculate\:within\:parentheses}\:\left[2+\left(6\cdot \:8\right)\right],\\2+\left(6\cdot \:8\right),\\\mathrm{Calculate\:within\:parentheses}\:\left(6\cdot \:8\right),\\6\cdot \:8=48,\\2+48,\\\mathrm{Add\:and\:subtract\:\left(left\:to\:right\right)}\:2+48,\\2+48=50,\\50-1`

`\mathrm{Add\:and\:subtract\:\left(left\:to\:right\right)}\:50-1,\\50-1=49`

`\mathrm{The\:Correct\:Answer\:is\:49}`

`\mathrm{Hope\:This\:Helps!!!}`

`\mathrm{-Austint1414}`

Answer 2

[2+(6times8)]-1

= [2+(6 * 8)] -1

= [2+(48)] -1

= 50 -1

= 49