Assuming base two number, then
1100110
= (1 × 2^6 ) + (1 × 2^5 ) + (0 × 2^4) +(0 × 2³) + (1 × 2²) + (1 × 2^1) + (0 × 2^0)
= 64 + 32 + 0 + 0 + 4 + 2 + 0 = 102
Hence =
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