Question

How many Al3+ ions are in a mole of AlBr3?

Answer 1

Answer: The number of
`Al^(3+)` ions in given compound is
`6.022* 10^(23)`

Step-by-step explanation:

We are given:

A chemical compound having chemical formula
`AlBr_3`

It is an ionic compound. This compound is formed by the complete transfer of electrons from 1 atom to another atom. The cation is formed by the loss of electrons by metals and anions are formed by gain of electrons by non metals.

It is formed by the combination of 1 aluminium ion and 3 bromine ions.

According to mole concept:

1 mole of an ionic compound contains
`6.022* 10^(23)` number of ions.

So, 1 mole of
`AlBr_3` will contain
`(1* 1* 6.022* 10^(23))=6.022* 10^(23)` number of aluminium ions

Hence, the number of
`Al^(3+)` ions in given compound is
`6.022* 10^(23)`

Answer 2

`AlBr_3` is a neutral molecule. which means the sum of oxidation numbers of all atoms is zero Bromine has a charge of -1. There are 3Br atoms that are added on
`Al^+^3` to give a neutral charge of 0.

`1Al` atom+
`3Br` atoms produce an electrically neutral salt.

This means there is only one
`Al^+^3` needed to form the salt.