Jenny's cats -> J
Daenna's cats -> D
J = 3D
J + D = 12 => D = 12 - J
I can now replace D in the first equation
J = 3 * (12 - J)
J = 36 - 3J
J + 3J = 36
4J = 36 => J = 36/4 = 9 cats
9 + D = 12 => D = 12 - 9 = 3 cats
Jenny has 9 cats, Daenna has 3 cats