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3 votes
Which expression is a perfect cube?

-8x^21 y^8
-64x^64 y^64
-125x^9 y^20
-216x^9 y^18

2 Answers

4 votes

Answer:

216x^9 y^18 is a perfect cube

Explanation:

To find out the expression that is a perfect cube, we need to take cube root for each expression


\sqrt[3]{8x^21 y^8} = \sqrt[3]{2^3x^(21) y^8}=2^{(3)/(3)} x^{(21)/(3)} y^{(8)/(3)}

8 is not divisible by 3 so it is not a perfect cube


\sqrt[3]{64x^64 y^64} = \sqrt[3]{2^6x^(64) y^(64)}=2^{(6)/(3)} x^{(64)/(3)} y^{(64)/(3)}

64 is not divisble by 3


\sqrt[3]{125x^9 y^20} = \sqrt[3]{5^3x^9 y^(20)}=5^{(3)/(3)} x^{(9)/(3)} y^{(20)/(3)}

20 is not divisible by 3


\sqrt[3]{216x^9 y^(18)} = \sqrt[3]{6^3x^9 y^(18)}=6^{(3)/(3)} x^{(9)/(3)} y^{(18)/(3)}=6x^3y^6

User Alisher Musurmonv
by
6.9k points
4 votes

-216x^9 y^18 is a perfect cube

User JustinJDavies
by
6.3k points