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Abigail has 2 and 1/7th cakes. She dropped 1 2/5th of the cakes. How much cake does she have left.

2 Answers

6 votes

Answer:


(26)/(35) th of the cake.

Explanation:

Abigail has
2(1)/(7) th cakes and she drops
1(2)/(5) of it.

To find out how much cake she is left with now, we just need to subtract the amount of cake she dropped from the amount of cake she had initially.


2(1)/(7) - 1(2)/(5)

Change these mixed fractions to improper fractions:


(15)/(7) -(7)/(5)

Taking the LCM to get:


((15*5)*(7*7))/(35) = (75-49)/(35) =(26)/(35)

Therefore, Abigail is now left with 26/35th of the cake.

User Sarel Botha
by
8.4k points
1 vote

Abigail has 2 and 1/7th cakes. She dropped 1 2/5th of the cakes

Abigail has
2(1)/(7) = (15)/(7) cakes

She dropped
1 (2)/(5) = (7)/(5) of the cakes

To find the amount of cake left, we subtract the amount of cake dropped from the whole cake

Cake left =
(15)/(7) - (7)/(5)

To subtract fractions make the denominators same

LCD is 7* 5 = 35


(15*5)/(7*5) - (7*7)/(5*7)


(75)/(35) - (49)/(35)


(75 - 49)/(35)


(26)/(35)


(26)/(35) of cake she have left

User Andrii Maletskyi
by
7.4k points

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