147k views
2 votes
An island has some portion submerged in water. Point A on the island is at negative 5 over 4 feet from the surface of the sea. Point B on the island is at negative 2 over 3 feet from the surface of the sea. Because negative 2 over 3 feet > negative 5 over 4 feet, what is true about the distance of the two points from the surface of the sea?

a. Point A is closer to the surface of the sea than point B.

b. Point B is closer to the surface of the sea than point A.

c. Both points are 1 and 11 over 12 feet from the surface of the sea.

d. Both points are 7 over 12 feet from the surface of the sea.

User MartinHH
by
8.4k points

2 Answers

7 votes

Answer:

The answer would be a. Point A is closer to the surface of the sea than point B.

-2/3 has a smaller absolute value than -5/4, meaning that -2/3 is close to 0


User Daniel Dewhurst
by
7.9k points
4 votes

Answer:

A. Point A is closer to the surface of the sea than point B.

Explanation:

Point A on the island is at -5/4 feet from the surface of the sea.

Point B on the island is at -2/3 feet from the surface of the sea.

-2/3 feet > -5/4 feet

=> -0.666 feet > -1.25 feet

-0.666 is close to zero.

So, answer will be A. Point A is closer to the surface of the sea than point B.

User Creemama
by
7.8k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories