Question

A 500-kg elevator is raised to a height of 20 m in 10 seconds. Calculate the power of the motor.

A) 98,000 W
B) 9,800 W
C) 2,500 W
D) 1000 W

Answer 1

<>"power = 500 kg x 9.8 m/s² x 20 m / 10s = 9800 watts."<>

Answer 2

Power, P =9800 W

Step-by-step explanation:

It is given that,

Mass of the elevator, m = 500kg

It is raised to a height of 20 m in 10 seconds

Power is defined as the work done per unit time.

`P=(W)/(t)`

Work done is given by :

`W=mgh`

h is the height

So,
`P=(mgh)/(t)`

`P=(500\ kg* 9.8\ m/s^2* 20\ m)/(10\ s)`

P = 9800 Watts

Hence, the power of the motor is 9800 W. The correct option is (b).