Question

Given f (x) = 1/5 (6 – x)^2 what is the value of f(16)?​

Answer 1

20

Explanation:

if f(x)=1/5(6-x)^2 when f(16)you will replace x by 16 then solve it like this

f(16)=1/5(6-16)^2

= 1/5(-10)^2

=1/5(100)

=20

Answer 2

f(16)=1/5(6-16)^2
f(16)=1/5(-10)^2
f(16)=1/5(100)
f(16)=20