Question 1

D-10-2d+7=8+d-10-3d

Question 2

$Solution,solve\:for\:d,\:d-10-2d+7=8+d-10-3d\quad :\quad d=1$

Steps:

d-10-2d+7=8+d-10-3d

$\mathrm{Subtract\:}d-10\mathrm{\:from\:both\:sides},\\d-10-2d+7-\left(d-10\right)=8+d-10-3d-\left(d-10\right)$

$\mathrm{Refine},\\-2d+7=8-3d$

$\mathrm{Subtract\:}7\mathrm{\:from\:both\:sides},\\-2d+7-7=8-3d-7$

$\mathrm{Simplify},\\-2d=-3d+1$

$\mathrm{Add\:}3d\mathrm{\:to\:both\:sides},\\-2d+3d=-3d+1+3d$

$\mathrm{Simplify},\\d=1$

$\mathrm{The\:Correct\:Answer\:is\:d=1}$

$\mathrm{Hope\:This\:Helps!!!}$

$\mathrm{-Austint1414}$

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