Question

I’m lost again can somebody help asap ??

Answer 1

Fully detailed and equipped information process right below. The answer for this question is "25" (simplified form).


`\mathbf{2^(28) * \Bigg((5^(- 2))/(2^3) \Bigg)^4 * \Bigg(5^(- 5) * 2^8 * 1 \Bigg)^(- 2)}`


`\mathbf{2^(28) * \Bigg((5^(- 2))/(2^3) \Bigg)^4 * \Bigg(2^8 * 1 * (1)/(5^5) \Bigg)^(- 2)}`


`\mathbf{2^(28) * \Bigg((5^(- 2))/(2^3) \Bigg)^4 * \Bigg(1 * (2^8 * 1)/(5^5) \Bigg)^(- 2)}`


`\mathbf{2^(28) * \Bigg((5^(- 2))/(2^3) \Bigg)^4 * \Bigg(1 * (256)/(3125) \Bigg)^(- 2)}`


`\mathbf{2^(28) * \Bigg((5^(- 2))/(2^3) \Bigg)^4 * \Bigg((3125)/(256) \Bigg)^2}`


`\mathbf{2^(28) * \Bigg((5^(- 2))/(2^3) \Bigg)^4 * (3125^2)/(256^2)}`


`\mathbf{2^(28) * \Bigg((1)/(2^3 * 5^2) \Bigg)^4 * (3125^2)/(256^2)}`


`\mathbf{2^(28) * \Bigg((1^4)/((2^3 * 5^2)^4) \Bigg) * (3125^2)/(256^2)}`


`\mathbf{2^(28) * \Bigg((1^4)/((5^2)^4 * (2^3)^4) \Bigg) * (3125^2)/(256^2)}`


`\mathbf{2^(28) * (1)/(2^(12) * 5^8) * (3125^2)/(256^2)}`


`\mathbf{(3125^2 * 1 * 2^(28))/(256^2 * 5^8 * 2^(12))}`


`\mathbf{(2^((28 - 12)) * 3125^2)/(256^2 * 5^8)}`


`\mathbf{(2^(16) * 3125^2)/(256^2 * 5^8)}`


`\mathbf{(2^(16) * (5^5)^2)/((2^8)^2 * 5^8)}`


`\mathbf{(2^(16) * 5^(10))/(2^(16) * 5^8)}`


`\mathbf{(2^(16) * 5^(10 - 8))/(2^(16))}`


`\mathbf{(5^(10 - 8))/(1)}`


`\mathbf{\therefore \quad 5^2}`


`\mathbf{\therefore \quad 25}`


`\boxed{\mathbf{\underline{\therefore \quad Final \: \: Answer \: \: is: \: 25}}}`

Hope it helps.