Question

The volume (in L) that would be occupied by 5.00 mols of 02 at STP is

Answer 1

Answer : The volume of oxygen at STP is 112.0665 L

Solution : Given,

The number of moles of
`O_2` = 5 moles

At STP, the temperature is 273 K and pressure is 1 atm.

Using ideal gas law equation :

`PV=nRT`

where,

P = pressure of gas

V = volume of gas

n = the number of moles

T = temperature of gas

R = gas constant = 0.0821 L atm/mole K (Given)

By rearranging the above ideal gas law equation, we get

`V=(nRT)/(P)`

Now put all the given values in this expression, we get the value of volume.

`V=((5moles)* (0.0821Latm/moleK)* (273K))/(1atm)=112.0665L`

Therefore, the volume of oxygen at STP is 112.0665 L