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Which equation is correct? a. cot x° = opposite ÷ adjacent b. sec x° = opposite ÷ adjacent c. sec x° = adjacent ÷ opposite d. cot x° = adjacent ÷ opposite

Which equation is correct? a. cot x° = opposite ÷ adjacent b. sec x° = opposite ÷ adjacent c. sec x° = adjacent ÷ opposite d. cot x° = adjacent ÷ opposite
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1 vote
Which equation is correct?

a. cot x° = opposite ÷ adjacent
b. sec x° = opposite ÷ adjacent
c. sec x° = adjacent ÷ opposite
d. cot x° = adjacent ÷ opposite

User Yuri Morales
by
8.2k points

1 Answer

3 votes
The answer is d.

cot x=adjacent over opposite
secant x=hypotenuse over adjacent

I hope this helps!
Best wishes.
-HuronGirl
User Kerisnarendra
by
8.0k points
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