Question

What is the equation in slope-intercept form for the line that passes

through the points (-1, 3) and (-2, -3)?

Answer 1

`\bf (\stackrel{x_1}{-1}~,~\stackrel{y_1}{3})\qquad (\stackrel{x_2}{-2}~,~\stackrel{y_2}{-3}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{-3-3}{-2-(-1)}\implies \cfrac{-6}{-2+1}\implies \cfrac{-6}{-1}\implies 6 \\\\\\ \begin{array}c \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-3=6[x-(-1)] \\\\\\ y-3=6(x+1)\implies y-3=6x+6\implies y=6x+9`