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Find three consecutive integers whose sum in 36

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ANSWER: 11, 12, 13

3 consecutive integers:

x \\ x + 1 \\ x + 2
"Sum" means Add


x + x + 1 + x + 2 = 36
Combine like-terms

3x + 3 = 36
Solve for X

3x + 3 = 36 \\
Subtract 3 from both sides

3x = 33
Divide by 3 on both sides

x = 11
11 + 1 = 12
11 + 2 = 13
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