Find three consecutive integers whose sum in 36

Question

asked Jul 16, 2019 217k views

1 Answer

DubDub · Answer 1 · 2019-07-20T13:04:44+0000

ANSWER: 11, 12, 13

3 consecutive integers:

$x \\ x + 1 \\ x + 2$
"Sum" means Add

x + x + 1 + x + 2 = 36

Combine like-terms

3x + 3 = 36

Solve for X

$3x + 3 = 36 \\$
Subtract 3 from both sides

3x = 33

Divide by 3 on both sides

x = 11

11 + 1 = 12
11 + 2 = 13