Answer:
two solutions (2,0) or (6,20)
Explanation:
y=x^2-3x+2, y=5x-10
y=x^2-3x+2=5x-10
x^2-2x-x+2=5(x-2)
x(x-2)-(x-2)=5(x-2)
(x-2)(x-1-5)=0
(x-2)(x-6)=0
x-2=0 or x-6=0
x=2 or x=6
x=2, y=5(2)-10=0
x=6, y=5(6)-10=20
The solution are (6,20) and (2,0)
The system of equations is:
y=x^2-3x+2 and
y=5x-10
Combining the two, x^2-3x+2=5x-10
Moving everything on one side, x^2-8x+12=0
Factoring, (x-6)(x-2)=0
x=6 or x=2
y=5(6)-10=20 or y=5(2)-10=0
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