Question

Help please!

Urgent Question!!!​

Answer 1

here,

coordinates of P(-2,3)

coordinates of Q(9,3)

coordinates of R(0,0)

now,

PR=QR

or, 0-(-2)+0-3=(0-9)+(0-3)

or, 2-3= -9-3

or, -1 = -12

Answer 2

Explanation:

Coordinates of Point R = (0, y).

We have PR = QR.

=> (-2 - 0)² + (6 - y)² = (9 - 0)² + (3 - y)².

=> 4 + (6 - y)² = 81 + (3 - y)²

=> y² - 12y + 40 = y² - 6y + 90

=> 6y + 50 = 0

=> y = -25/3.

Hence the answer is (0, -25/3).

Coordinates of Point S = (x, 0).

We have PS = QS.

=> (-2 - x)² + (6 - 0)² = (9 - x)² + (3 - 0)²

=> (-2 - x)² + 36 = (9 - x)² + 9

=> x² + 4x + 40 = x² - 18x + 90

=> 22x = 50

=> x = 25/11.

Hence the answer is (25/11, 0).