Question

Solve 27^2x-6 = 3^9+x

Answer 1

`27^(2)` x - 6 =
`3^(9)` + 6

First, Evaluate the power:

`27^(2)` x - 6 =
`3^(9)` + 6

729x - 6 = 19683 + x

Next, move the variable to the left side and change it's sign, then the constant to the right side and change its sign:

729x - 6 = 19683 + x

Next, collect like terms and add the numbers:

729x - x = 19683 + 6

728x = 19689

Finally divide both sides of the equation by 728 (any expression divided by itself equals 1):

x = 19689 / 728

x = 27
`(33)/(728)`