Question

A force of 1.5 × 102 N is exerted on a charge of 1.4 × 10–7 C that is traveling at an angle of 75° to a magnetic field.

If the charge is moving at 1.3 × 106 m/s, what is the magnetic field strength?

A) 8.2 × 102 T
B) 8.5 × 102 T
C) 3.2 × 103 T
D) 6.4 × 1010 T

Answer 1

The magnetic field strength would be; B) 8.5 × 102 T

Answer 2

B)
`B = 8.5 * 10^2 T`

Step-by-step explanation:

As we know that force on a moving charge is given by

`\vec F = q(\vec v * \vec B)`

here we know that the angle between velocity and magnetic field is 75 degree

so force is given as

`F = qvBsin75`

here we will have

`F = 1.5 * 10^2 N`

`q = 1.4 * 10^(-7) C`

`v = 1.3 * 10^6 m/s`

now from above formula we will have

`1.5 * 10^2 = (1.4 * 10^(-7))(1.3 * 10^6)Bsin75`

now from above equation

`B = 8.5 * 10^2 T`