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KN bisects JKL. Solve for x.

KN bisects JKL. Solve for x.-example-1
User Arnav Rao
by
7.5k points

2 Answers

1 vote

Answer:

B. 40

Explanation:

We have been given that segment KN bisects angle JKL.

Since we know that bisects means diving exactly into two equal parts, so measure of angle LKN will be equal to measure of angle JKN.


m\angle LKN=m\angle JKN

Upon substituting our given information in above equation we will get,


3x-50=x+30

Let us solve for x by combining like terms.


3x-x-50=x-x+30


2x-50=30


2x-50+50=30+50


2x=80

Upon dividing both sides of our equation by 2 we will get,


(2x)/(2)=(80)/(2)


x=40

Therefore, the value of x is 40 and option B is the correct choice.

User Christophe Blin
by
8.0k points
5 votes

Because KN is a bisector, both angles would be the same.


Set both equations to equal each other then solve for x.

x +30 = 3x -50

Add 50 to each side:

x +80 = 3x

Subtract 1x from each side:

80 = 2x

Divide both sides by 2:

x = 80 /2

x = 40

User Arla
by
7.7k points