Question

1. A right triangle LMN is given where: side MN = 8 side NL (the hypotenuse) =

10 What is the length of side LM?*

Answer 1

Explanation:

`\underline{ \underline{ \text{Given}}} :`

• Length of MN ( Base ) = 8
• Length of NL ( Hypotenuse ) = 10

`\underline{ \underline{ \text{To \: find}}} :`

• Length of LM ( Perpendicular )

`\underline{ \underline{ \text{Using \: pythagoras \: theorem}}} :`

`\boxed{ \sf{ {Hypotenuse}^(2) = {Perpendicular}^(2) + {Base}^(2) }}`

⤑
`\sf{ Perpendicular = \sqrt{ {(Hypotenuse)}^(2) - {(Base)}^(2) } }`

⤑
`\sf{ \sqrt{ {(10)}^(2) - {(8)}^(2) } }`

⤑
`\sf{ √(100 - 64)}`

⤑
`\sf{ √(36)}`

⤑
`\boxed{ \sf{6\: units}}`

`\pink{ \boxed{ \boxed{ \tt{Our \: final \: answer : \boxed{ \underline { \tt{6 \: units}}}}}}}`

Hope I helped ! ツ

Have a wonderful day / night ! ♡

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