Question

If the pressure of 16 moles of ideal gas is 690 mmHg, and the volume is 1 L, what is the temperature in Kelvin

Answer 1

0.691 K

Step-by-step explanation:

Data:

Moles = n = 16 mole

Pressure = P = 690 mmHg = 0.908 atm

Volume = V = 1 L

Temperature = ?

Gas Constant = R = 0.0821 atm.L.mol⁻¹.K⁻¹

Formula Used:

P V = n R T

Solving for T,

T = P V / n R

Putting Values,

T = 0.908 atm × 1 L / 16 mol × 0.0821 atm.L.mol⁻¹.K⁻¹

T = 0.691 K