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What is the remainder when the polynomial 8x^2 +4-3 is divided by 2x-1

User Jlalcazar
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To find the remainder, we can use the remainder theorem.

To do this, first we need to set 2x - 1 equal to 0.

2x - 1 = 0

Solve for x.

2x = 1

x = 1/2

Now that we have this value, we can solve for the remainder of this polynomial by replacing each x value with 1/2.

8(1/2)^2 + 4(1/2) - 3 = 1

The remainder is 1.

User Renaldo
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