Question

If 200 mg of HCl is added to water to achieve a final volume of 1L, what is the final pH?

Answer 1

hope this helps ..................

Answer 2

The pH of the solution is 2.26 .

Step-by-step explanation:

Mass of HCl = 200 mg = 0.200 g

1 mg = 0.001 g

Moles of HCl =
`n=(0.200 g)/(36.5 g/mol)=0.005479 mol`

Volume of the solution ,V= 1 L

Molarity of HCl solution =
`(n)/(V)`

`[HCl]=(0.005479 mol)/(1 L)=0.005479 mol/L`

1 mole of HCk gives 1 mole of hydrogen ion and 1 mole of chloride ions.

`[HCl]=[H^+]=[Cl^-]=0.005479 mol/L`

The pH of the solution is negative logarithm of hydrogen ion concentration:

`pH=-\log[H^+]`

`pH=-\log[0.005479 mol/L]=2.26`

The pH of the solution is 2.26 .