Look at the picture.
We have the triangle and the parallelogram.
The formula of an area of a triangle

We have b = 5 and h = 3. Substitute:

The fromula of an area of a parallelogram:

We have b = 5 and h = 3. Substitute:

The area of polygon:

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Other method. (look at the second picture).
We have the three congruent triangles. The area of the polygon is equal three times the area of a one triangle.

b = 5, h = 3. Subsitute.

The area of the polygon:
