Question

An 8 Newton wooden block slides across a horizontal wooden floor at constant velocity. What is the magi notice of the force of kinetic friction between the block and the floor

Answer 1

The force of kinetic friction between the block and the floor is 2.4 N

Step-by-step explanation:

The given parameters are;

The weight of the block = 8 Newtons

The velocity of the block = Constant velocity

Taking the kinetic friction for wood,
`\mu _k` = 0.3, we have;

The normal reaction of the block on horizontal ground, N = The weight of the block = 8 N

The force of kinetic friction between ,
`F_k` =
`\mu _k` × N

Therefore, we have;

The force of kinetic friction between the block and the floor,
`F_k` = 0.3 × 8 N = 2.4 N.