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An isosceles right triangle whose legs are 6 is rotated about one of its legs to generate a right circular cone. What is the volume of the cone?

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Answer:


V = 72 \pi

Explanation:

The radius of the base is one of the legs, so it is 6.

The height of the cone is the other leg, so it is also 6.


V = (1)/(3) \pi r^2 h


V = (1)/(3) (\pi)(6^2)(6)


V = (\pi)(36)(2)


V = 72 \pi

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