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1. What are the domain restrictions of q^2−7q−8/q^2+3q−4

q≠1 and q≠−8
q≠−1 and q≠4
q≠1 and q≠−4
q≠−1 and q≠8

2. What are the domain restrictions of the expression y^2−3y−40/y^2+9y+20 ?

y≠−5
y≠8
y≠4
y≠−4
y≠5
y≠−8

2 Answers

2 votes

Answer:

1: q ≠ 1 and q ≠ -8

2: -4 and -5

Explanation:

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User Omniwombat
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8.3k points
7 votes

(1)

we are given


(q^2-7q-8)/(q^2+3q-4)

We know that any function is undefined when denominator =0

so, we will set denominator =0

and then we can solve for q


q^2+3q-4=0

now, we can factor it


(q+4)(q-1)=0


(q+4)=0


q=-4


(q-1)=0


q=1

so,

q≠1 and q≠−4............Answer

(2)

we are given


(y^2-3y-40)/(y^2+9y+20)

Since, any function is undefined when denominator =0

so, we set denominator =0

and then we can solve for y


y^2+9y+20=0


(y+4)(y+5)=0


(y+4)=0


y=-4


(y+5)=0


y=-5

so,

y≠−5

y≠−4.............Answer

User Janez Kuhar
by
7.6k points