Question

At a carnival, food tickets cost $2 each and ride tickets cost $3 each. A total of $1,240 was collected at the carnival. The number of food tickets sold was 10 less than twice the number of ride tickets sold.

The system of equations represents x, the number of food tickets sold, and y, the number of ride tickets sold.

2x + 3y = 1240

x = 2y – 10

How many of each type of ticket were sold?

Answer 1

in the equation as we can say x= 2y-10.

so, substitute x=2y-10 everywhere then the x in 1240 gets cancelled with 2y-10 then solve the remaining you will get 4y-20+3y=1240

7y=1260

y=1260/7

y=180

then substitute the value of y everywhere

2x+3y=1240

2x+3(180)=1240

2x=1240-540

2x=700

x=350

DONE.