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What is the absolute value of the complex number -4-√2i

2 Answers

4 votes

Answer:

3√2

Explanation:

Recall that "absolute value" often denotes "distance." We could apply the distance formula here, obtaining

distance = absolute value of -4 - √2*i =

= √( [-4]^2 + [√2*i]^2 ) = √(16+2) = √18 = 3√2

User Krfurlong
by
8.3k points
5 votes

Answer:


\sqrt[3]{2}

Explanation:

If the complex number is given in the form of ( a+bi)

Then absolute value of the complex number will be =
\sqrt{a^(2)+b^(2)  }

Now the given complex number is (
-4 \sqrt[-i]{2}

So in this number a = ( -4 ) and b =
\sqrt[-]{2}

Therefore, absolute value will be =
\sqrt{(-4)^(2)+(\sqrt[-]{2})^(2)}

=
√(16+2)

=
√(18)

=
√(9*2)

=
\sqrt[3]{2}

So absolute value will be
\sqrt[3]{2}.

User Saurabh Bhola
by
8.3k points