Question

What is the equation of the line in slope-intercept form?

Line on a coordinate plane. The line runs through points begin ordered pair negative 2 comma 0 end ordered pair and begin ordered pair 0 comma 5 end ordered pair.

Answer 1

Learn From My Mistakes :)

Explanation:

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Answer 2

`f(x)=(5)/(2)x+5`

Explanation:

1)Given two points (-2,0) and (0,5) let's find the slope, then the equation of the line, in slope-intercept form. Notice the last parameter to be found was the linear parameter "b" :

`m=(y_(2)-y_(1))/(x_(2)-x_(1))=(5-0)/(0+2)=(5)/(2)\Rightarrow \left\{\begin{matrix}0 =&(5)/(2)(-2)&+b \\ 5=& (5)/(2)(0) &+b\\ \end{matrix}\right.\Rightarrow b=5 \therefore f(x)=(5)/(2)x+5`