Question

If the spring constant is doubled , what value does the period have for a mass on a spring?

A. The period would double by square sqrt (2)
B.The period would be halved by sqrt (2)
C. The period would increase by sqrt (2)
D. The period would decrease by sqrt (2)

Answer 1

B) the period would be halved by sqrt (2) THIS IS THE RIGHT ANSWER FOR PLATO USERS

Step-by-step explanation:

Answer 2

D. The period would decrease by sqrt (2)

Step-by-step explanation:

The period of a mass-spring system is given by:

`T=2\pi \sqrt{(m)/(k)}`

where

m is the mass

k is the spring constant of the spring

If the spring constant is doubled,

k' = 2k

So the new period will be

`T'=2\pi \sqrt{(m)/((2k))}=(1)/(√(2))(2\pi \sqrt{(m)/(k)})=(T)/(√(2))`

So the correct answer is

D. The period would decrease by sqrt (2)