94.8k views
4 votes
Can someone answer these?

Can someone answer these?-example-1

1 Answer

2 votes

Nine

Basically you are using d = r * t

Frequency is 1 / t

d is more commonly represented by lambda (
\lambda). Lambda is the wavelength.

so the formula
\lambda = c / f

More commonly it is written as
\lambda*f = c.

Givens

c = 3*10^8 m/s


\lambda = 0.1 nm = 0.1 nm *[1 m /1 * 10^9 nm] = 0.1 * 10^ - 9 meters.

f = ??

f =
(3*10^8)/(0.1 * 10^-9)

f = 3 * 10^8 * 10^9 / 0.1 = 3 * 10^18

Answer: C

Ten


\lambda = c/f


\lambda = 3*10^8 / 1 * 10^16


\lambda = 3*10^-8 meters


\lambda = 30 * 10^-9 meters = 30 nm

Answer: D


User Andrei B
by
8.9k points

No related questions found