Question

At the height of 800 meters, a skydiver falls from an airplane flying horizontally at 40 m/sec. What is the horizontal distance of the skydivers travel before they "hit" the ground?

Answer 1

The horizontal distance traveled by the skydiver is 510.8 m.

Step-by-step explanation:

Given;

height of fall, h = 800 m

initial velocity of the airplane, u = 40 m/s

The time to fall to the ground is calculated as;

`t = \sqrt{(2h)/(g) } \\\\t = \sqrt{(2 * 800)/(9.81) }\\\\t = 12.77 \ s`

The horizontal distance or range of the motion is calculated as;

R = ut

R = 40 m/s x 12.77 s

R = 510.8 m

Therefore, the horizontal distance traveled by the skydiver is 510.8 m.