Question

Consider the figure below. Abraham cut regular pentagon ABCDE into quadrilateral BEGC. Which of the following statements is true about quadrilateral BEGC? (picture included)

Answer 1

Answer:3, 4, and 6

Step-by-step explanation: Trust me I took the test. Hope it helps

Answer 2

Let 'n' be the number of side of a regular polygon each angle are equal and sum of each angle equal to (n-2)×180.
`\\`∴For a regular pentagon have five equal side, n=5
`\\` ∴ sum of each angle = (n-2)×180=3×180 = 540. and ecah angle = 540÷5=108°. Therefore ∠BCG = 108° and ∠ABC =108°
`\\` Here BE is one of the diagonal of regular pentagon ABCDE. BE divide ∠ABC in 1:2 ratio
`\\` Therefore ∠ABE : ∠CBE = 36: 72
`\\`∴ ∠GCB + ∠CBE = 108° +72°=180°