Answer : option 2,4 and 5 are true statements
![(3p+1)/(6p) - (2p-3)/(2p^2)](https://img.qammunity.org/2019/formulas/mathematics/high-school/hxlnoogrit60b0bl6h9bv86i0rhipkh8ld.png)
We have 6p and 2p^2 in the denominator
Least common denominator LCD = 6p^2
Now we need to make the denominators same
![((3p+1)*p)/(6p*p) - ((2p-3)*3)/(2p^2*3)](https://img.qammunity.org/2019/formulas/mathematics/high-school/vo2spkm2024kdzsfsfshbyxm0ehphm677t.png)
![((3p^2+p))/(6p^2) - ((6p-9))/(6p^2)](https://img.qammunity.org/2019/formulas/mathematics/high-school/frqdskk4xgci4hpmmre2odmi4suisveyzu.png)
So first fraction becomes
![((3p^2+p))/(6p^2)](https://img.qammunity.org/2019/formulas/mathematics/high-school/lqlhd24kbzu21b1zuowonr3xuq195gh7tg.png)
We find the difference by subtracting the numerators
![((3p^2+p-6p + 9))/(6p^2)](https://img.qammunity.org/2019/formulas/mathematics/high-school/vi5lwvbxqqddbxo2gtn4zkqz47n88q0lu1.png)
![((3p^2- 5p + 9))/(6p^2)](https://img.qammunity.org/2019/formulas/mathematics/high-school/ghsubn8888cd0kdp8hlmqr7ozm4gdh2zae.png)
The resulting is a rational expression
So option 2, 4 and 5 are true statements