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If you had a total sample of 35 candium- 15 M&Mium, 12 Skittlitium and 8 MPeanuttium. What is the relative abundance for each

User Sateesh K
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1 Answer

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Given:

Total Candium = 35

# of M&M = 15

# of Skittlitium = 12

# of Peanutttium = 8

To determine:

The relative abundance for each

Step-by-step explanation:

Relative abundance = amount of each item in the sample/Sample total

M&M = 15/35 = 0.429 (or) 42.9 %

Skittlitium = 12/35 = 0.343 (or) 43.3 %

Peanuttium = 8/35 = 0.229 (0r) 22.9%

User Samir Karmacharya
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