Question

The product of two consecutive positive even intergers is 14 more than their sum. Find the integers.

Answer 1

Answer:4 and six

Step-by-step explanation: n = the first number ( n + 2 ) = the second number

Set up an equation using the information n × ( n + 2 ) = n + ( n + 2 ) + 14 doing the operations gives.

n 2 + 2 n = 2 n + 16 Subtract 2 n from both sides

n 2 + 2 n − 2 n = 2 n − 2 n + 16

This results in n 2 = 16

Take the square root of both sides.

√ n 2 = ± √ 16

This gives n = 4 or n = − 4

The negative answer is invalid n = 4 add 2 to find n + 2 , the second number

4 + 2 = 6