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Graph the hyperbola with equation quantity x plus 3 squared divided by 25 minus the quantity of y plus 5 squared divided by 4 = 1

User Jocelynn
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2 Answers

1 vote

Answer:

Explanation:

As we know the general formula of the hyperbola is:

(x-h)²/a² - (y-k)²/b² = 1, where

  • (h,k) is the center
  • a is the semi-major axis
  • b is the semi-minor axis

In this situation, the equation is:

(x+3)²/25 - (y+5)²/4 = 1

=> the center is: (-3, -5)

a = 5

b = 2

  • As we know their slopes are +/-
    (b)/(a) so

-5 = +2/5 (-3) + b ---> b= -3.8

-5 = -2/5 (-3) + b ---> b= -6.2

Hence, you plot the equations y=2/5x -3.8 and y = -2/5 x - 6.2 by assigning values of x and plotting them against y as the attached photo.

Hope it will find you well.

Graph the hyperbola with equation quantity x plus 3 squared divided by 25 minus the-example-1
User Tombruijn
by
8.3k points
5 votes

Hello,

Please, see the graph in the attached file.

Thanks.

Graph the hyperbola with equation quantity x plus 3 squared divided by 25 minus the-example-1
User Tuminoid
by
7.4k points

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