8<2/3(3y-6) 8 \leqslant (2)/(3) (3y - 6)

Question

8<2/3(3y-6)

`8 \leqslant (2)/(3) (3y - 6)`

Answer 1

8<=2/3(3y-6)

distribute

8<= 2y -4

add 4 to each side

12 <=2y

divide by 2

6<=y