U = { q, r, s, t, u, v, w, x, y, z }
A = { q, s, u, w, y } → A' = { r, t, v, x , z }
B = { q, s, y, z } → B' = { r, t, u, v, w, x }
C = { v, w, x, y, z }
A ∩ B' = { q, s, u, w, y } ∩ { r, t, u, v, w, x } = { u, w }
B ∩ A' = { q, s, y, z } ∩ { r, t, v, x , z } = { z }
(A ∩ B') ∪ (B ∩ A') = { u, w } ∪ { z } = { u, w, z }
Answer: (A ∩ B') ∪ (B ∩ A') = { u, w, z }
A' = U - A, B' = U - B
The union A ∪ B, is the set of all things that are members of either A or B.
The intersection A ∩ B, is the set of all things that are members of both A and B.