Question

the temperature of a 6.0 G sample of glass change from 20 degrees Celsius to 45 degrees Celsius when it absorbs 550 J of heat what is this specific heat of this glass sample

Answer 1

`0.367 \; \text{J} \cdot \text{g}^(-1) \cdot \text{K}^(-1)`

The specific heat of a substance measures the energy required to raise the temperature of a one-unit-mass sample of this substance by one unit.

The question provides the following information:

• Energy change
  `Q = 550 \; \text{J}`
• Temperature change
  `\Delta T = 45 -20 = 25 \; \text{K}`
• Mass of the sample
  `m = 6.0 \; \text{g}`

The specific heat of this substance measures the energy change
`Q` for a process involving:

• Temperature change
  `\Delta T = 1 \; \text{K}`
• Mass of the sample
  `m = 1\; \text{g}`

Apply the formula

`c = Q/(m \cdot \Delta T)\\\phantom{c} = 550 \; \text{J} / (6 \; \text{g} \cdot 25 \; \text{K})\\\phantom{c} = 0.367 \; \text{J} \cdot \text{g}^(-1) \cdot \text{K}^(-1)`