Given the volume of HCl solution = 30.00 mL
Molarity of HCl solution = 0.1000 M
Molarity, moles and volume are related by the equation:
Molarity =
![(Moles of solute)/(Volume of solution (L))](https://img.qammunity.org/2019/formulas/chemistry/college/tdbn1bsz0ejtoe2dk49m04ww37nooywbhe.png)
Converting volume of HCl from mL to L:
![30.00 mL * (1 L)/(1000mL)=0.030000 L](https://img.qammunity.org/2019/formulas/chemistry/college/ov8b6pu22mn50lh4l9h3t42hrmj7dsv1ij.png)
Calculating moles of HCl from volume in L and molarity:
![0.03000 L * (0.1000mol)/(L)= 0.003000 mol HCl](https://img.qammunity.org/2019/formulas/chemistry/college/39itm1t026j49ef0ccau7f2ym9m69wmidn.png)
The final moles would be reported to 4 sig figs. So the correct answer will be 0.03000 mol HCl
Correct option: C. 0.03000mol